Optimal. Leaf size=36 \[ a^2 x-\frac{(a+b)^2 \coth (c+d x)}{d}-\frac{b^2 \tanh (c+d x)}{d} \]
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Rubi [A] time = 0.0851578, antiderivative size = 36, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.13, Rules used = {4141, 1802, 207} \[ a^2 x-\frac{(a+b)^2 \coth (c+d x)}{d}-\frac{b^2 \tanh (c+d x)}{d} \]
Antiderivative was successfully verified.
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Rule 4141
Rule 1802
Rule 207
Rubi steps
\begin{align*} \int \coth ^2(c+d x) \left (a+b \text{sech}^2(c+d x)\right )^2 \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (a+b \left (1-x^2\right )\right )^2}{x^2 \left (1-x^2\right )} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=\frac{\operatorname{Subst}\left (\int \left (-b^2+\frac{(a+b)^2}{x^2}-\frac{a^2}{-1+x^2}\right ) \, dx,x,\tanh (c+d x)\right )}{d}\\ &=-\frac{(a+b)^2 \coth (c+d x)}{d}-\frac{b^2 \tanh (c+d x)}{d}-\frac{a^2 \operatorname{Subst}\left (\int \frac{1}{-1+x^2} \, dx,x,\tanh (c+d x)\right )}{d}\\ &=a^2 x-\frac{(a+b)^2 \coth (c+d x)}{d}-\frac{b^2 \tanh (c+d x)}{d}\\ \end{align*}
Mathematica [B] time = 0.700138, size = 82, normalized size = 2.28 \[ \frac{4 \text{sech}(c+d x) \left (a \cosh ^2(c+d x)+b\right )^2 \left (a^2 d x \cosh (c+d x)+\sinh (d x) \left ((a+b)^2 \text{csch}(c) \coth (c+d x)-b^2 \text{sech}(c)\right )\right )}{d (a \cosh (2 (c+d x))+a+2 b)^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.033, size = 64, normalized size = 1.8 \begin{align*}{\frac{1}{d} \left ({a}^{2} \left ( dx+c-{\rm coth} \left (dx+c\right ) \right ) -2\,ab{\rm coth} \left (dx+c\right )+{b}^{2} \left ( -{\frac{1}{\cosh \left ( dx+c \right ) \sinh \left ( dx+c \right ) }}-2\,\tanh \left ( dx+c \right ) \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.20152, size = 96, normalized size = 2.67 \begin{align*} a^{2}{\left (x + \frac{c}{d} + \frac{2}{d{\left (e^{\left (-2 \, d x - 2 \, c\right )} - 1\right )}}\right )} + \frac{4 \, a b}{d{\left (e^{\left (-2 \, d x - 2 \, c\right )} - 1\right )}} + \frac{4 \, b^{2}}{d{\left (e^{\left (-4 \, d x - 4 \, c\right )} - 1\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.11021, size = 265, normalized size = 7.36 \begin{align*} -\frac{{\left (a^{2} + 2 \, a b + 2 \, b^{2}\right )} \cosh \left (d x + c\right )^{2} - 2 \,{\left (a^{2} d x + a^{2} + 2 \, a b + 2 \, b^{2}\right )} \cosh \left (d x + c\right ) \sinh \left (d x + c\right ) +{\left (a^{2} + 2 \, a b + 2 \, b^{2}\right )} \sinh \left (d x + c\right )^{2} + a^{2} + 2 \, a b}{2 \, d \cosh \left (d x + c\right ) \sinh \left (d x + c\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.26052, size = 88, normalized size = 2.44 \begin{align*} \frac{a^{2} d x - \frac{2 \,{\left (a^{2} e^{\left (2 \, d x + 2 \, c\right )} + 2 \, a b e^{\left (2 \, d x + 2 \, c\right )} + a^{2} + 2 \, a b + 2 \, b^{2}\right )}}{e^{\left (4 \, d x + 4 \, c\right )} - 1}}{d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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